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Thread: Dyno Guys
          
   
   

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  1. #31
    skids72's Avatar
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    small block? intake center-line? rod length?

  2. #32
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    DADNOVA... with the new flow metrics, you're getting 511hp@6500 and 498tq@4500 but I'm still assuming ICL 110* and 6.544 rod length (1.636:1 rod ratio probably too long?).. I think it's safe to say you'll be making somewhere around 500/500 with that motor.

    -Chris

  3. #33
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    Quote Originally Posted by DADNOVA
    [Can you help me with the HP on your dyno with this configuration

    Block-dart 9.325 deck, bore 4.125 cubic inch 427
    Heads- AFR 227 68cc chambers int. 2.1 ext. 1.6 full race ported
    lift flow int ex
    .2 138 112
    .3 207 150
    .4 258 190
    .5 294 207
    .55 298 213
    .6 302 220
    .65 305 225
    .7 309 230
    crank- bore 4.125 stroke 4
    carb- 750 demon
    pistons -JE dish .115 comp 11.25
    cam -roller int dur. 292 ex 302 lob sep 112
    Int duration 292
    Ex duration 302
    Int lift at cam .403
    Ex lift at cam .398
    Total lift int.604 ex 597
    rockers -jessel 1.5 total lift int .604 ex .597
    headers -1 5/8 pipes 3" H pipe installed
    intake -performer rpm duel plane
    elec -fan and water pump[
    Does that help
    You don't need a Jessel system.
    All you really need is a good 7/16 roller rocker with a girdle.
    Save the money for something else.

  4. #34
    erik erikson's Avatar
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    Quote Originally Posted by skids72
    DADNOVA... with the new flow metrics, you're getting 511hp@6500 and 498tq@4500 but I'm still assuming ICL 110* and 6.544 rod length (1.636:1 rod ratio probably too long?).. I think it's safe to say you'll be making somewhere around 500/500 with that motor.

    -Chris
    6.544 rods??????

  5. #35
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    Erik... I know... sounds too long but I was working from the 1.636 rod ratio for lack of a better idea... would need a really tall deck for that(?)

    -Chris
    Last edited by skids72; 02-11-2007 at 09:33 AM.

  6. #36
    erik erikson's Avatar
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    Quote Originally Posted by skids72
    Erik... I know... sounds too long but I was working from the 1.636 rod ratio for lack of a better idea... would need a really tall deck for that...

    -Chris
    Based on a 9.20 deck height about the longest rod you can run is 6.250.
    In the large stroke engines 6.125 is about it.
    What happens is due to the stroke and rod length the piston pin location gets up into the bottom compression ring on the large cube engines.
    Are you calculating compression distance
    DECK HEIGHT - 1/2 STROKE - ROD LENGTH - DECK CLEARANCE = COMP. HEIGHT ??

  7. #37
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    6 ince rods
    What program are you using?
    My freinds Virtural Engine Dyno shows 700 HP with 670 tourqe.
    Guess I will have to take it to a Dyno shop and spend the money.

  8. #38
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    I'm just using swept volume and tweaking combustion space (chamber+gasket+dome/dish+deck height) to get the target compression of 11.25:1 ... didn't want to make a dissertation of this or anything. BTW using a more realistic rod (6.1" for 1.525:1 ratio) makes 508hp/496tq in the simulation (not much difference).

    Thanks... I'm still pretty new to this and trying to learn most I can from you guys that have been there.

    -Chris

    DADNOVA - 700HP eh? Do you know intake lobe center line for that cam? I'm just plugging in numbers here. I'm treating your 292/302 as seat-to-seat duration. BTW I would be very surprised if you're making 1.6HP/ci in a stroker with 11.25:1 compression...
    Last edited by skids72; 02-11-2007 at 09:50 AM.

  9. #39
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    Quote Originally Posted by DADNOVA
    6 ince rods
    What program are you using?
    My freinds Virtural Engine Dyno shows 700 HP with 670 tourqe.
    Guess I will have to take it to a Dyno shop and spend the money.
    One of our 434's on meth. just cracked the 700 hp barrier.
    That is with 14 to 1 comp ratio and fully CNC'D 23* Brodix heads and very stout roller cam.
    This is why I hate some of the dyno sims they are a joke.
    There is no way you will go to 700hp.
    You still did'nt give the cam's duration at .050 so there is no real way to figure any of this.

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