Thread: Stock pusrod length..

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Anyone know the stock pushrod length in a 390 ford found in the '63 Mercury Monterey? Summit lists it at 9.157, but the book at the local O'reilly auto parts suggests 9.5 and larger.

I dont have a caliper to measure the stock ones, sorry. hoping someone on here knows or has a quick way to find out for sure.


thanks!

Originally Posted by gun4hire

Anyone know the stock pushrod length in a 390 ford found in the '63 Mercury Monterey? Summit lists it at 9.157, but the book at the local O'reilly auto parts suggests 9.5 and larger.

I dont have a caliper to measure the stock ones, sorry. hoping someone on here knows or has a quick way to find out for sure.


thanks!

You don't need a caliper. All you need is a ruler or tape that is graduated down to 32nds. 9.157" will be 9 and 5/32nds and 9.5 will be 9 1/2. Matter of fact, one that has 16ths will work. 9.157" will be 9 and two and a half 16ths.

Thanks again!

I'm a work right now, but I'll try to use a tape measure tomorrow and find out. I guess I was thinking it would have been documented somewhere online.

Tech ; Hit the nail on the head, as he allways does.
There were several differant cams used in those.
There were also 3 differant size rocker stands that went
over the rocker studs. what year head? what valves?
what head gasget? Best just to follow Tech's instuctions.
They don't even tell pushrod lengths in my ford performance book!
Kurt

I measured it with a regular tape mesure and it looks like 9 and 9.5/16ths = 9.59375 or ~ 9.594

FYI I also found this page which seems to confirm it should be 9.59:

http://www.ford-fe.com/Pushrods.htm


thanks again guys...

maybe you want check your math 1/16=62.5 thou. x 5 = 312.....ted

Originally Posted by ted dehaan

maybe you want check your math 1/16=62.5 thou. x 5 = 312.....ted

huh?

Apologies if I'm wrong... but where did the "x5 = 312" come from?

I'm putting 9.5 and dividing by 16 and getting 0.59375

OR by following your process 1/16= (62.5 thousandths or 0.062.5) x (9.5) = 0.59375 + 9 = 9.594

The overall length measured was 9 and 9.5/16 (aka 9 and 19/32)

working on an old car may be new to me, but please dont tell me mathematics are failing me too!!! LOL!

I remeasured the pushrod excluding the ball ends and get just a smidge over the 9" mark.

I guess I should clarify: exactly how these should be measured? When I've ordered for my late-model cars, I've always included the complete length.

Ted, I think he was saying nine inches plus nine and one half sixteenths of an inch. Nine and a half sixteenths would be 0.59375", which when added to the nine inches, would be 9.59".

^^ exactly.

ha I am really sorry I upset that much but I have never seen any body measure something at 9 and a half sixteenths don't worry I won't bother you again sorry ..ted

Originally Posted by ted dehaan

ha I am really sorry I upset that much but I have never seen any body measure something at 9 and a half sixteenths don't worry I won't bother you again sorry ..ted

No, man its not like that. You're right, I should have posted it originally as 9 and 19/32nds .. its just that 16ths were as small as my measuring tape would go. lol.

No worries, I didn't get upset. Life's too short.