Thread: Eternal Triangle
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10-03-2008 04:54 PM #1
Eternal Triangle
Designing a framework for a hoist and my meager math skills are failing me.
Frame has a right triangle in it that is 2' 9" on the base leg and 5' on the vertical leg.
A 90dg angle
B base of hypotenuse
C top of hypotenuse
a base leg
b hypotenuse
c vertical leg
Questions- What is the angle of B and C? What is the length of b?Thanks for help.theres no foo like an old foo
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10-03-2008 05:49 PM #2
A squared + B squared = C squared. A base of 33" X 33" = 1089 ". B vertical leg of 60" X 60" = 3600". C hypotenuse 1089" + 3600" = 4689". Square root of 4689" = 68.476". Don't know about the angles. It's been thirty-five years since I had a geometry class. My daughter just came into the room .She's a college girl. Mom"s yelling at us to come to dinner! I'll try to get the angles figured out after dinner.
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10-03-2008 06:35 PM #3
My stomach is full and my High School Valedictorian daughter figured out the angles. Angle at base of hypotenuse is 61.2 degrees. Angle at top is 28.8 degrees.
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10-03-2008 07:13 PM #4
Thank you kind sir and kudos to your daughter.theres no foo like an old foo
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